(2y^2-4y+6)/2y=

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Solution for (2y^2-4y+6)/2y= equation: 



(2y^2-4y+6)/2y=

We move all terms to the left:

(2y^2-4y+6)/2y-()=0



Domain of the equation: 2y!=0

y!=0/2

y!=0

y∈R



We add all the numbers together, and all the variables

(2y^2-4y+6)/2y=0

We multiply all the terms by the denominator


(2y^2-4y+6)=0

We get rid of parentheses

2y^2-4y+6=0

a = 2; b = -4; c = +6;
Δ = b2-4ac
Δ = -42-4·2·6
Δ = -32
Delta is less than zero, so there is no solution for the equation

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